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/* stpcpy.c -- copy a string and return pointer to end of new string
Copyright (C) 1992, 1995, 1997-1998, 2006, 2009-2013 Free Software
Foundation, Inc.
NOTE: The canonical source of this file is maintained with the GNU C Library.
Bugs can be reported to bug-glibc@prep.ai.mit.edu.
This program is free software: you can redistribute it and/or modify it
under the terms of the GNU General Public License as published by the
Free Software Foundation; either version 3 of the License, or any
later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>. */
#include <config.h>
#include <string.h>
#include <stdlib.h>
#undef __stpcpy
#if defined(_LIBC) || (defined(__MACH__) && defined(stpcpy))
# undef stpcpy
#endif
#ifndef weak_alias
# define __stpcpy stpcpy
#endif
/* Copy SRC to DEST, returning the address of the terminating '\0' in DEST. */
char *
__stpcpy (char *dest, const char *src)
{
char *d = dest;
const char *s = src;
do
*d++ = *s;
while (*s++ != '\0');
return d - 1;
}
#ifdef weak_alias
weak_alias (__stpcpy, stpcpy)
#endif
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