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findall tests
=============
>>> import re2
>>> re2.set_fallback_notification(re2.FALLBACK_EXCEPTION)
This one is from http://docs.python.org/library/re.html?#finding-all-adverbs:
>>> re2.findall(r"\w+ly", "He was carefully disguised but captured quickly by police.")
['carefully', 'quickly']
This one makes sure all groups are found:
>>> re2.findall(r"(\w+)=(\d+)", "foo=1,foo=2")
[('foo', '1'), ('foo', '2')]
When there's only one matched group, it should not be returned in a tuple:
>>> re2.findall(r"(\w)\w", "fx")
['f']
Zero matches is an empty list:
>>> re2.findall("(f)", "gggg")
[]
If pattern matches an empty string, do it only once at the end:
>>> re2.findall(".*", "foo")
['foo', '']
>>> re2.findall("", "foo")
['', '', '', '']
>>> import re
>>> re.findall(r'\b', 'The quick brown fox jumped over the lazy dog')
['', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']
>>> re2.findall(r'\b', 'The quick brown fox jumped over the lazy dog')
['', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']
>>> re2.set_fallback_notification(re2.FALLBACK_QUIETLY)
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