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/*
* default memory allocator for libavutil
* Copyright (c) 2002 Fabrice Bellard.
*
* This library is free software; you can redistribute it and/or
* modify it under the terms of the GNU Lesser General Public
* License as published by the Free Software Foundation; either
* version 2 of the License, or (at your option) any later version.
*
* This library is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with this library; if not, write to the Free Software
* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
*/
/**
* @file mem.c
* default memory allocator for libavutil.
*/
#include "common.h"
/* here we can use OS dependant allocation functions */
#undef malloc
#undef free
#undef realloc
#ifdef HAVE_MALLOC_H
#include <malloc.h>
#endif
/* you can redefine av_malloc and av_free in your project to use your
memory allocator. You do not need to suppress this file because the
linker will do it automatically */
/**
* Memory allocation of size byte with alignment suitable for all
* memory accesses (including vectors if available on the
* CPU). av_malloc(0) must return a non NULL pointer.
*/
void *av_malloc(unsigned int size)
{
void *ptr;
#ifdef MEMALIGN_HACK
long diff;
#endif
/* let's disallow possible ambiguous cases */
if(size > (INT_MAX-16) )
return NULL;
#ifdef MEMALIGN_HACK
ptr = malloc(size+16);
if(!ptr)
return ptr;
diff= ((-(long)ptr - 1)&15) + 1;
ptr += diff;
((char*)ptr)[-1]= diff;
#elif defined (HAVE_MEMALIGN)
ptr = memalign(16,size);
/* Why 64?
Indeed, we should align it:
on 4 for 386
on 16 for 486
on 32 for 586, PPro - k6-III
on 64 for K7 (maybe for P3 too).
Because L1 and L2 caches are aligned on those values.
But I don't want to code such logic here!
*/
/* Why 16?
because some cpus need alignment, for example SSE2 on P4, & most RISC cpus
it will just trigger an exception and the unaligned load will be done in the
exception handler or it will just segfault (SSE2 on P4)
Why not larger? because i didnt see a difference in benchmarks ...
*/
/* benchmarks with p3
memalign(64)+1 3071,3051,3032
memalign(64)+2 3051,3032,3041
memalign(64)+4 2911,2896,2915
memalign(64)+8 2545,2554,2550
memalign(64)+16 2543,2572,2563
memalign(64)+32 2546,2545,2571
memalign(64)+64 2570,2533,2558
btw, malloc seems to do 8 byte alignment by default here
*/
#else
ptr = malloc(size);
#endif
return ptr;
}
/**
* av_realloc semantics (same as glibc): if ptr is NULL and size > 0,
* identical to malloc(size). If size is zero, it is identical to
* free(ptr) and NULL is returned.
*/
void *av_realloc(void *ptr, unsigned int size)
{
#ifdef MEMALIGN_HACK
int diff;
#endif
/* let's disallow possible ambiguous cases */
if(size > (INT_MAX-16) )
return NULL;
#ifdef MEMALIGN_HACK
//FIXME this isn't aligned correctly, though it probably isn't needed
if(!ptr) return av_malloc(size);
diff= ((char*)ptr)[-1];
return realloc(ptr - diff, size + diff) + diff;
#else
return realloc(ptr, size);
#endif
}
/**
* Free memory which has been allocated with av_malloc(z)() or av_realloc().
* NOTE: ptr = NULL is explicetly allowed
* Note2: it is recommended that you use av_freep() instead
*/
void av_free(void *ptr)
{
/* XXX: this test should not be needed on most libcs */
if (ptr)
#ifdef MEMALIGN_HACK
free(ptr - ((char*)ptr)[-1]);
#else
free(ptr);
#endif
}
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